Mogą istnieć dwa wodorotlenki cyny jako że jej wartościowość jest (+ II) lub (+IV) ---------------------------------------------------------------------------------------------------- [latex]Sn(OH)_2[/latex] [latex]\%Sn= frac{m_{Sn}}{m_{Sn}+m_{O}+m{H}}= frac{n_{Sn}M_{Sn}}{n_{Sn}M_{Sn}+n_{O}M_{O}+n_{H}M_{H}} =frac{M_{Sn}}{M_{Sn}+2M_{O}+2M_{H}} =[/latex] [latex] =frac{119}{119+2*16+2*1}=77,8\%[/latex] [latex]\%O= frac{2M_{O}}{M_{Sn}+2M_{O}+2M_{H}} =frac{2*16}{119+2*16+2*1}=20,9\%[/latex] [latex]\%H= frac{2M_{H}}{M_{Sn}+2M_{O}+2M_{H}} = frac{2*1}{119+2*16+2*1}=1,3\%[/latex] ---------------------------------------------------------------------------------------------------- [latex]Sn(OH)_4[/latex] [latex]\%Sn= frac{m_{Sn}}{m_{Sn}+m_{O}+m{H}}= frac{n_{Sn}M_{Sn}}{n_{Sn}M_{Sn}+n_{O}M_{O}+n_{H}M_{H}} =frac{M_{Sn}}{M_{Sn}+4M_{O}+4M_{H}} =[/latex] [latex] =frac{119}{119+4*16+4*1}=63,6\%[/latex] [latex]\%O= frac{4M_{O}}{M_{Sn}+4M_{O}+4M_{H}} =frac{4*16}{119+4*16+4*1}=34,2\%[/latex] [latex]\%H= frac{4M_{H}}{M_{Sn}+4M_{O}+4M_{H}} = frac{4*1}{119+4*16+4*1}=2,2\%[/latex] ---------------------------------------------------------------------------------------------------- Glin ma tylko jedną wartościowość (+ III) więc i jeden wodorotlenek ---------------------------------------------------------------------------------------------------- [latex]Al(OH)_3[/latex] [latex]\%Al= frac{m_{Al}}{m_{Al}+m_{O}+m{H}}= frac{n_{Al}M_{Al}}{n_{Al}M_{Al}+n_{O}M_{O}+n_{H}M_{H}} =frac{M_{Al}}{M_{Al}+3M_{O}+3M_{H}}= [/latex] [latex]= frac{27}{27+3*16+3*1}=34,6\% [/latex] [latex]\%O=frac{3M_{O}}{M_{Al}+3M_{O}+3M_{H}}= frac{3*16}{27+3*16+3*1}=61,5\%[/latex] [latex]\%H=frac{3M_{H}}{M_{Al}+3M_{O}+3M_{H}}= frac{3*1}{27+3*16+3*1}=3,9\% [/latex]
