Proszę o pilne zrobienie zadania z załącznika. Z góry dziękuję :)

[latex]log_{2}64=log_2 2^6=6log_2 2 = 6 \ log_2 512=log_2 2^9=9log_2 2=9 \ log_2 0,25=log_2 4^{-1}=log_2 4^{-2}=-2 \ log_2 frac{1}{1024}=log_2 frac{1}{2^{10}}=log_2 2^{-10}=-10 \ log_2 0,125=log_2 frac{1}{8}=log_2 frac{1}{2^3}=log_2 2^{-3} =-3 \ log_4 2 = log_4 sqrt{4}=log_4 4^{frac{1}{2}}=frac{1}{2} \ log_4 8=log_4 sqrt{64}=log_4 sqrt{4^3}=log_4 4^{frac{3}{2}}=frac{3}{2} \ log_4 frac{1}{1024}=log_4 frac{1}{4^5}=log_4 4^{-5}=-5 \ [/latex] [latex]log_4 frac{1}{sqrt{2}}=log_4 2^{-frac{1}{2}}=log_4 left(4^{frac{1}{2}} ight)^{-frac{1}{2}}=log_4 4^{-frac{1}{4}}=-frac{1}{4} \ log_{sqrt{2}}4=log_{sqrt{2}} left(left(sqrt{2} ight)^2 ight)^2=log_{sqrt{2}}left(sqrt{2} ight)^4=4 \ log_{sqrt{2}}32=log_{sqrt{2}} left( (sqrt{2})^2 ight)^5=log_{sqrt{2}}(sqrt{2})^{10}=10 \ log_{3}sqrt{3}=log_{3} 3^{frac{1}{2}}=frac{1}{2} \ log_{3}sqrt{27}=log_{3}sqrt{3^3}=log_{3} 3^{frac{3}{2}}=frac{3}{2} \ [/latex] [latex]log_{3}frac{1}{81}=log_{3} frac{1}{3^4}=log_{3}3^{-4}=-4 \ log_{5} 625= log_5 5^4=4 \ log_5 0,04 = log_5 frac{4}{100}=log_5 frac{1}{25}=log_5 frac{1}{5^2}=log_5 5^{-2}=-2 \ hbox{Ze wzoru:} \ log_a a^{b}=b[/latex]