rozwiąż równanie : a) (6x-5)do kwadratu=-60x+34 b ) x(do kwadratu) -6x=0 z góry dzięki daje naaaaj :)

(6x-5)² = -60x + 34 36x² - 60x + 25 = -60x + 34 36x² = 9 x² = [latex] frac{9}{36} [/latex] x1=[latex] sqrt{ frac{9}{36}} = frac{3}{6} = frac{1}{2} [/latex] x2= [latex]- sqrt{ frac{9}{36}} =- frac{3}{6} =- frac{1}{2} [/latex] x² - 6x =0 x(x-6)=0 x=0 dla x-6=0 x=6 x=0 ; x=6

a) [latex](6x-5)^{2} =-60x+34 \ 36 x^{2} -2*6x*5+25=-60x+34 \ 36 x^{2} -60x=-60x+9 \ 36 x^{2} =9 /:36 \ x^{2} = frac{1}{4} \ x= frac{1}{2} vee x=- frac{1}{2} [/latex] b) [latex] x^{2} -6x=0[/latex] Δ=[latex]36-4*1*0[/latex] Δ=[latex] sqrt{36} =6[/latex] [latex] x_{1} = frac{6-6}{2} =0\ x_{2} = frac{6+6}{2} =6[/latex]