zad 4 PROSZE WYJAŚNIĆ ! W ZAŁ.

[latex]a) log_73\ b) 6^x=3^x :3^x\ (frac{6}{3})^x=1\ x=0\ c) 3^{x+1}=4\ 3^x=frac{4}{3}\ log_3frac{4}{3}\ \ d) 2^{3x-1}=5\ 2^3^x=10\ log_810\ \ e) 4^{2x+3}=1\ 4^2^x=frac{1}{64}\ \ log_16frac{1}{64}[/latex] [latex]\ f) 5^x=2^{x+1}\ 5^x=2^x*2 :2^x\ (frac{5}{2})^x=2\ \ log_frac{5}{2}2\ g) (frac{1}{3})^x= (frac{1}{2})^x^-^1 :(frac{1}{2})^x\ (frac{2}{3})^x=2\ log_frac{2}{3}2 \ h) 4^{1-x}=5^x\ frac{4}{4^x}=5^x\ 4=20^x\ log_2_04[/latex]