Proszę o obliczenie logarytmów :) Zadania w załączniku

[latex]2.30\a)log4+log25=log(4*25)=log100=2\\b)log50+log20=log(50*20)=log1000=3\\c)log_{6}2+log_{6}18=log_{6}(2*18)=log_{6}=36=2\\d)log_{2}96-log_{2}6=log_{2}frac{96}{6}=log_{2}16=4\\e)log_{9}108-log_{9}4=log_{9}frac{108}{4}=log_{9}27=frac{3}{2}\\f)log_{frac{1}{2}}6-log_{frac{1}{2}}3=log_{frac{1}{2}}frac{6}{3}=log_{frac{1}{2}}2=-1\\2.31\a)2log_{3}6-log_{3}4=log_{3}6^{2}-log_{3}4=log_{3}36-log_{3}4=log_{3}9=2\\b)log8+3log5=log8+log125=log1000=3[/latex] [latex]\\c)log_{4}3+2log_{4}frac{2sqrt{3}}{3}=log_{4}3+log_{4}(frac{2sqrt{3}}{3})^{2}=log_{4}3+log_{4}frac{12}{9}=\log_{4}(3*frac{12}{9})=log_{4}4=1\\d)2log_{frac{1}{2}}5+4log_{frac{1}{2}}2-2log_{frac{1}{2}}10=log_{frac{1}{2}}5^{2}+log_{frac{1}{2}}2^{4}-log_{frac{1}{2}}10^{2}=\log_{frac{1}{2}}25+log_{frac{1}{2}}16-log_{frac{1}{2}}100=log_{frac{1}{2}}frac{25*16}{100}=log_{frac{1}{2}}=log_{frac{1}{2}}4=-2\\[/latex] [latex]e)log_{3}3-3log_{3}2+log_{3}24=log_{3}3-log_{3}8+log_{3}24=\log_{3}(frac{3}{8}*24)=log_{3}9=2\\f)log_{frac{1}{4}}18+log_{frac{1}{4}}8-2log_{frac{1}{4}}3=log_{frac{1}{4}}18+log_{frac{1}{4}}8-log_{frac{1}{4}}9=\=log_{frac{1}{4}}(frac{18*8}{9})=log_{frac{1}{4}}16=-2\g)log15+log2+2log5-logfrac{3}{4}=log15+log2+log25-logfrac{3}{4}=\=log(frac{15*2*25}{frac{3}{4}})=log(750*frac{4}{3})=log1000=3[/latex]