Oblicz: a)[latex] frac{3}{4} +frac{1}{4}.[latex]1 b)[latex] frac{7}{8}.4+6. frac{5}{12}= [/latex] c)[latex] frac{50}{6}- frac{1}{6}.1 frac{1}{2}=[/latex]5= d)[latex] [latex](1frac{3}{8}+2frac{5}{6}).12=[/latex]

też to mam więc doliczam się  do pytania :D

oblicz wartość wyrażenia a)[latex] (frac{2}{3})^{5}*(frac{3}{4})^{5} [/latex] b)[latex] (frac{1}{2})^{4}*(frac{2}{3})^{4} [/latex] c)[latex] (1frac{1}{2})^{50}*(frac{2}{3})^{50} [/latex] d)[latex] (2frac{1}{3})^{4}*(frac{6}{7})^{4} [/latex]

oblicz wartość wyrażenia a)[latex] (frac{2}{3})^{5}*(frac{3}{4})^{5} [/latex] b)[latex] (frac{1}{2})^{4}*(frac{2}{3})^{4} [/latex] c)[latex] (1frac{1}{2})^{50}*(frac{2}{3})^{50} [/latex] d)[latex] (2frac{1}{3})^{4}*(frac{6}{7})^{4} [/latex]...

Oblicz: [latex]1 frac{7}{9} + 2frac{3}{10} = [/latex] [latex] 2frac{7}{8} + 3frac{1}{6} = [/latex] [latex]c) frac{8}{9} - frac{2}{5} = [/latex] [latex] frac{7}{8} - frac{4}{5} = [/latex] [latex]4frac{5}{6} - frac{1}{4} = [/latex] [latex]

Oblicz: [latex]1 frac{7}{9} + 2frac{3}{10} = [/latex] [latex] 2frac{7}{8} + 3frac{1}{6} = [/latex] [latex]c) frac{8}{9} - frac{2}{5} = [/latex] [latex] frac{7}{8} - frac{4}{5} = [/latex] [latex]4frac{5}{6} - frac{1}{4} = [/latex] [...

Oblicz a)[latex] (frac{1}{4})^{8}:(frac{1}{2})^{8} [/latex] b)[latex] 7^{3}:(2frac{1}{3})^{3} [/latex] c)[latex](3frac{1}{2})^{8}:(1frac{3}{4})^{8} [/latex] d)[latex](1frac{2}{3})^{5}:(2,5)^{5} [/latex]

Oblicz a)[latex] (frac{1}{4})^{8}:(frac{1}{2})^{8} [/latex] b)[latex] 7^{3}:(2frac{1}{3})^{3} [/latex] c)[latex](3frac{1}{2})^{8}:(1frac{3}{4})^{8} [/latex] d)[latex](1frac{2}{3})^{5}:(2,5)^{5} [/latex]...

Oblicz. [latex] frac{3}{5} + frac{8}{5} [/latex] [latex] 1frac{7}{9} + 2frac{3}{9} [/latex]

Oblicz. [latex] frac{3}{5} + frac{8}{5} [/latex] [latex] 1frac{7}{9} + 2frac{3}{9} [/latex]...

Oblicz a) {[latex][1frac{1}{2}-[(6frac{1}{2}-4frac{3}{4}):(5-frac{1}{3})+frac{1}{2}]]:frac{5}{8}=[/latex] b)[2frac[latex][2frac{5}{6}+frac{3}{4}:(frac{2frac{1}{4}}{3frac{1}{2}cdot8-25}-1)]cdot4frac{4}{5}=[/latex]

Oblicz a) {[latex][1frac{1}{2}-[(6frac{1}{2}-4frac{3}{4}):(5-frac{1}{3})+frac{1}{2}]]:frac{5}{8}=[/latex] b)[2frac[latex][2frac{5}{6}+frac{3}{4}:(frac{2frac{1}{4}}{3frac{1}{2}cdot8-25}-1)]cdot4frac{4}{5}=[/latex]...