Kto obliczy kto wie? daje 18 !   http://www.fizyka.zs.lubawa.pl/text/zestaw1.pdf Zestaw 1 zadanie czwarte strona 35

[latex]a) frac12cdot[(-1)^8+(-1)^8]=frac12cdot(1+1)=frac12cdot2=1\ b) (-3frac13)^3cdot0,3^4-(-frac12)^3cdot(1frac13)^2=(-frac{10}{3})^3cdot(frac{3}{10})^4+frac{1}{2^3}cdot(frac43)^2=\ =-frac{10^3}{3^3}cdotfrac{3^4}{10^4}+frac{1}{2^3}cdotfrac{4^2}{3^2}=-frac{3}{10}+frac{1}{2^3}cdotfrac{2^4}{3^2}=-frac{3}{10}+frac{2}{9}=-frac{27}{90}+frac{20}{90}=-frac{7}{90}\ [/latex] [latex]c) (1frac13)^3cdot(-3frac34)^2:3-(frac13)^2=(frac43)^3cdot(-frac{15}{4})^2:3-frac19=\ =frac{4^3}{3^3}cdot(-frac{3^2cdot5^2}{4^2})cdotfrac13-frac19=frac{4cdot25}{3^2}-frac19=\ =frac{100}{9}-frac19=frac{99}{9}=11\ d) (-0,3)^2:0,1-0,2^3cdot(2frac12)^2=frac{9}{100}cdotfrac{10}{1}-frac{1}{5^2}cdot(frac52)^2=\ =frac{9}{10}-frac{1}{25}cdotfrac{25}{4}=frac{9}{10}-frac14=frac{36}{40}-frac{10}{40}=frac{26}{40}=frac{13}{20}\ [/latex] [latex]e) (-0,1)^4cdot20^3+(1frac12)^3:(-0,3)^2=frac{1}{10^4}cdot2^3cdot10^3+(frac32)^3cdot(frac{10}{3})^2=\ =frac{2^3}{10}+frac{3^3}{2^3}cdotfrac{10^2}{3^2}=frac{8}{10}+frac{3cdot100}{2^3}=frac{8}{10}+frac{300}{8}=frac{8}{10}+frac{75}{2}=frac{8}{10}+frac{375}{10}=\ =frac{383}{10}=38frac{3}{10}[/latex]