Rozwiąż równania : a) 6x3+x2-4x+1=0 b)(x+3)(x2-4)=0 Pilne daje naj :)

[latex]a) \\6x^{3} +x^2-4x+1=0 \\6x^3-2x^2+3x^2-x-3x+1=0\\2x^2(3x-1)+x(3x-1)-(3x-1)=0\\(2x^2+x-1) (3x-1)=0 \\ 2x^2+x-1=0 vee 3x-1=0 [/latex] [latex] Delta =b^2-4ac =1^2 -4*2* (-1)= 1+8=9\ \sqrt{Delta }=sqrt{ 9}=3 \ \x_{1}=frac{-b- sqrt{Delta } }{2a}=frac{1-3}{2 *2}=frac{-2}{4}=-frac{1}{2} \ \x_{2}=frac{-b+ sqrt{Delta } }{2a}=frac{1+3}{2 *2}=frac{4}{4}=1\\lub\\3x-1=0\\3x=1 / :3\\x=frac{1}{3}\\rozwiazanie: x=-frac{1}{2} vee x=-frac{1}{2} vee x=1[/latex] [latex]b)\\(x+3)(x^2-4)=0\\(x+3)(x -2)(x+2)=0\\x+3=0 vee x -2=0 vee x+2=0\\x=-3 vee x =2 vee x=-2[/latex]