Rozwiąż równania wielomianowe: a) x3 +2x2-4x-8=0 b) x3-9x2+14x+24=0

Witaj. a) [latex]x^{3}+2x^{2}-4x-8=0\\x^{2}(x+2)-4(x+2)=0\\(x+2)(x^{2}-4)=0\\(x+2)(x+2)(x-2)=0\\(x+2)^{2}(x-2)=0\\x=-2 lub x=2\\xin{-2;2}[/latex] b) [latex]x^{3}-9x^{2}+14x+24=0\\x^{3}+x^{2}-10x^{2}-10x+24x+24=0\\x^{2}(x+1)-10x(x+1)+24(x+1)=0\\(x+1)(x^{2}-10x+24)=0\\(x+1)(x-6)(x-4)=0\\x=-1 lub x=6 lub x=4\\xin{-1;4;6}[/latex]