Zapisz wyrażenie w najprostszej postaci. Liczy się matematyka, ćwiczenia strona 53, zadanie 10[latex]a) frac{10x(6y+5)}{5} + frac{8x +6y}{2 } = \ b) frac{12x-8y}{4} - frac{15x-20y}{5} = [/latex]

a) =[latex] frac{60xy+50x}{5} + frac{8x+6y}{2} [/latex] =12xy + 10x + 4x + 3y=14x+ 12xy+3y b) = 3x - 2y - 3x+ 4y = 2y

[latex]a) frac{10x(6y+5)}{5} + frac{8x +6y}{2 } =frac{2[10x(6y+5)]}{10}+frac{5(8x+6y)}{10}=frac{20x(6y+5)}{10}+frac{5(8x+6y)}{10}=\ =frac{120xy+100x}{10}+frac{40x+30y}{10}=frac{120xy+140x+30y}{10}=12xy+14x+3y\ \ b) frac{12x-8y}{4} - frac{15x-20y}{5} =frac{5(12x-8y)}{20}-frac{4(15x-20y)}{20}=frac{60x-40y}{20}-frac{60x-80y}{20}=\ =frac{60x-40y-60x+80y}{20}=frac{40y}{20}=2y[/latex]