Prosze o rozwiazanie :) Rozwiąż układy równań metoda podstawiania ( x-2y=0 (3x + y =7 (2x+y=6 (x-3y= -4

1. (x=2y (6y+y=7 /:6 (x=2y (y=1 (y=1 (x=2 2. (2x=-y+6/:2 (x-3y=-4 (x=-1/2y +3 (x-3y=-4 (x=-1/2y+3 (-1/2y+3-3y= -4 (x=1/2y-3 (-3 i1/2y =-7 /:(-1) (x=-1/2y-3 (3i1/2y=7 /: 3 i 1/2 (y=2 (x=-1 + 3 (y=2 (x=2 Liczę  na naj