Oblicz x a) [latex]log_{3}x=2+2log_{3}2[/latex] b) [latex]log x=-1+2log5[/latex] c) [latex]log_{0,5}x=1+log_{0,5}6-2log_{0,5}3[/latex] prosze o pelne rozwiazanie

[latex]\a) \log_3x=log_39+log_32^2, x>0 \ \log_3x=log_3(9*4) \ \log_3x=log_336 \ \x=36 \b) \logx=-log10+log5^2 \ \logx=log(0,1*25) \ \logx=log2,5 \ \x=2,5[/latex] c) [latex]\log_{0,5}x=log_{0,5}0,5+log_{0,5}(6:3^2) \ \log_{0,5}x=log_{0,5}(0,5*frac23) \ \log_{0,5}x=log_{0,5}frac13 \ \x=frac13[/latex]