Rozwiąż nierówność a) ([latex] sqrt{2} [/latex] - x) * ([latex] sqrt{2} [/latex] + 1) ≥ 2√2 + 3 b) [latex] frac{3-x}{6} - frac{2+x}{3} <1[/latex]

[latex]a) \\( sqrt{2} - x) * ( sqrt{2} + 1) geq 2 sqrt{2} + 3 \\2+sqrt{2}-sqrt{2}x-xgeq 2 sqrt{2} + 3 \\ -sqrt{2}x-xgeq 2 sqrt{2} + 3-2 -sqrt{2} \\ -x(sqrt{2}+1)geq sqrt{2} + 1 /:-(sqrt{2}+1)\\xleq -1\\xin(-infty ,-1>[/latex] [latex]b)\\ frac{3-x}{6} - frac{2+x}{3} <1 /*6\\3-x-2(2+x)< 6\\3-x-4-2x< 6\\ -x -2x< 6+4-3\\ -3x< 7 /:(-3)\\x>-frac{7}{3}\\x in(-frac{7}{3},+infty)[/latex]