Do 0,1kg wody o temperaturze 12C dolano 0,4kg wody o temperaturze 19 C Oblicz temperaturę wody po jej wymieszaniu

[latex]m_{1}=0,1 [kg]\\T_{1}=12 [^{o}C]\\m_{2}=0,4 [kg]\\T_{2}=19 [^{o}C][/latex] Układamy bilans cieplny: [latex]Q_{1}+Q_{2}=0\\m_{1}c_{w}(T_{k}-T_{1})+m_{2}c_{w}(T_{k}-T_{2})=0\\m_{1}(T_{k}-T_{1})+m_{2}(T_{k}-T_{2})=0\\T_{k}=frac{m_{1}T_{1}+m_{2}T_{2}}{m_{1}+m_{2}}=17,6 [^{o}C][/latex]