Rozwiąż równanie kwadratowe [latex] x^{2} + sqrt{2} x-4=0[/latex]

x² + √2 x - 4 = 0    ⇒  a=1,  b=√2,    c=-4  Δ = b² -4ac = 2+16 =18    ⇒  √Δ = 3√2 [latex]x_1 = frac{-b- sqrt{Delta} }{2a}= frac{- sqrt{2}-3sqrt{2} }{2} =frac{-4sqrt{2} }{2}=-2sqrt{2} \ \ x_2 = frac{-b+ sqrt{Delta} }{2a}= frac{- sqrt{2}+3sqrt{2} }{2} =frac{2sqrt{2} }{2}=sqrt{2} [/latex]