Zad 1 oblicz Oblicz: 2,6 +3,4 : 1,7 + 6/7 ( - 2 1/3 zad 2 Sprowadź do najprostszej postaci wyrażenie : ( x-2y ) ^ - (2x+y) (2x-y) +2x (2y-3) Zad 3 Rozwiąż 3x/2 - 2x/3 =10

[latex]1.\\2,6+3,4:1,7+frac{6}{7}(-2frac{1}{3}) = 2,6+2+frac{6}{7}*(-frac{7}{3})=4,6 - 2 = 2,6[/latex] [latex]2.\\(x-2y)^{2}-(2x+y)(2x-y) + 2x(2y-3)=\\=x^{2}-4xy+4y^{2}-(4x^{2}-y^{2})+4xy-6x=\\=x^{2}+4y^{2}-4x^{2}+y^{2}-6x=\\=-3x^{2}-6x+5y^{2}[/latex] [latex]3.\\frac{3x}{2}-frac{2x}{3} = 10 |*6\\3*3x-2*2x = 10*6\\9x - 4x = 60\\5x = 60 /:5\\x = 12[/latex]