Obliczyć granicę funkcji: lim->0 sin2x/sin3x

[latex] lim_{x o 0} frac{sin2x}{sin3x} = lim_{x o 0} (frac{sin2x}{2x}*frac{3x}{sin3x}*frac{2}{3}) = lim_{x o 0} (frac{sin2x}{2x}:frac{sin3x}{3x}*frac{2}{3}) = \ = 1:1*frac{2}{3} = frac{2}{3}[/latex]