Wykaż, że: a) log√8+log√6=log√3+log4 b) log√18-log√12=log√6-log2 c) log√20+log√2=1/2+log2 d)log125↓25+log125↓3125+log125↓^5do ósmej=5

a) log√8+log√6=log√3+log4 log (√8*√6)=log(√3  *4) log√48=log 4√3 log 4√3=log4√3 b) log√18-log√12=log√6-log2 log(√18:√12)=log(√6/2) log√(3/2)=log (√6/2) log [ √3/√2]=log(√6/2) log [ (√3√2) /(√2*√2)]=log(√6/2) log(√3/2)=log(√3/2) c) log√20+log√2=1/2+log2 log (√20*√2)=1/2+log2 log(√40)=1/2+log2 log (2√10) =1/2+log2 log 2+log√10=1/2+log2          log√10=1/2 1/2+log2=1/2+log2 d)log125↓25+log125↓3125+log125↓^5do ósmej=5 log 125  (25*3125*5^8)=5 log 125  ( 5²*5^ 5*5^8)=5 log125 ( 5 ^ 15)=5 log125 ( 5³)^5=5 log 125 ( 125^5)=5 5=5