napisze mi ktoś to równanie i zad 1 z góry dzięki daje naj

[latex]1.\\m = 3,5 kg\T_{p} = 30^{o}C\T_{k} = 100^{o}C\c = 4200frac{J}{kg*^{o}C}\szukane:\Q = ?[/latex] [latex]Q = c*m*Delta T}\\Delta T = T_{k} - T_{p} = 100^{o}C - 30^{o}C = 70^{o}C\\Q = 4200frac{J}{kg*^{o}C}*3,5kg*70^{o}C\\Q = 1 029 000 J=1 029 kJ = 1,029 MJ[/latex] 1 kJ = 1000 J 1 MJ = 1 000 000 J [latex]2.[/latex] [latex]c = frac{P*t}{m(T_{k}-T_{p})}= frac{2000W*27s}{0,694kg*(40^{o}C - 25^{o}C)}approx5187frac{J}{kg*^{o}C}[/latex]