zad 1 oblicz ile energii należy dostarczyć kostce lodu o masie 2kg i temperaturze -20 stopni C doprowadzic do stanu goracej pary wodnej o temperaturze 160 stopni C. Z góry dziekuję :)

Q1- Ciepło potrzebne na ogrzanie 2kg lodu o 20oC m=2kg                                                                   Q=m x c x ∆T c=2100                                                         Q1=2kg x 2100  x 20 ∆T=20                                                                 Q1=84000 J Q1=?   Q2- Ciepło potrzebne na stopienie 2 kg lodu m=2kg                                                                     Q=ct x m ct=335000                                                            Q2=335000 x 2kg Q2=?                                                                          Q2=670000 J   Q3- Ciepło potrzebne na ogrzanie 2 kg wody o 100 m=2kg                                                                      Q=m x c x ∆T     c=4200                                                            Q3=2kg x 2100  x 100 ∆T=100                                                                 Q3=420000 J Q3=?   Q4- Ciepło potrzebne na wrzenie 2 kg wody m=2kg                                                                       Q=cp x m cp=2258000                                                           Q4=2258000  x 2kg                                                        Q4=?                                                                           Q4=4516000 J        Q5- Ciepło potrzebne na ogrzanie pary wodnej o 60 m=2kg                                                                        Q=m x c x ∆T     c=1840                                                              Q5=2kg x 1840  x 60 ∆T=60                                                                      Q5=220800 J                        Q5=?                         Q= Q1 + Q2 + Q3 + Q4 + Q5 Q= 84000J + 670000J + 420000J + 4516000J + 220800J Q= 5910800J = 5910,8 KJ