1. [latex] frac{a^{2} sqrt{3} }{4} =3 sqrt{3} /*4 \ a^{2} sqrt{3} =12 sqrt{3} /: sqrt{3} \ a^{2} =12 \ [/latex] [latex]a=2 sqrt{3} [/latex] ∨ [latex]a=-2 sqrt{3} [/latex] [latex]H= frac{a sqrt{3} }{2} \ H= frac{2 sqrt{3}* sqrt{3} }{2} \ H=3[/latex] [latex]r= frac{1}{2}a= sqrt{3} [/latex] [latex]V= frac{1}{3} r^{2} pi H[/latex] [latex]V= frac{1}{3}* ( sqrt{3}) ^{2} *3 pi \ V=3 pi [/latex] Odp. A 2.[latex] frac{ a^{2} sqrt{3} }{4} =9 sqrt{3} /*4 \ a^{2} sqrt{3} =36 sqrt{3} /: sqrt{3} \ a^{2} =36[/latex] [latex]a=6[/latex] ∨ [latex]a=-6[/latex] [latex]a=6[/latex] [latex]H= frac{ asqrt{3} }{2} = frac{ 6sqrt{3} }{2} = 3sqrt{3} [/latex] [latex]r= frac{1}{2} a= frac{1}{2} *6=3[/latex] [latex]V= frac{1}{3} r^{2} H pi \ V= frac{1}{3} 3^{2} *3 sqrt{3} =9 sqrt{3} [/latex] 3. Załącznik 4. Załącznik 5. [latex]P= pi r^{2} frac{ alpha }{360} = pi 36* frac{50}{360} =5 pi [/latex] Odp. D 6.[latex]P= pi 36* frac{8}{36} = 8 pi [/latex] Odp. D 7. Pole całkowite to 2*Pole boczne stożka o promieniu 6 i tworzącej 6 [latex]P=2* pi rl=2*6*6 pi =72 pi [/latex] Odp. D 8. Załącznik
