bardzo prosze opomoc daje naj rozwiąż równania A. [latex]2 x^{2} +5x-3 extgreater 0[/latex] b. [latex]-3 x^{2} -2x+1 leq 0[/latex] c.[latex] frac{x+3}{x-3} = frac{x}{x-1} [/latex]

A) [latex]2x^2 + 5x-3 > 0 \ 2x^2 + 5x-3 = 0[/latex] Δ = [latex]25 + 24 = 49[/latex] [latex]x_1 = frac{-5-7}{4} = -3 \ x_2 = frac{-5+7}{4} = frac{1}{2}[/latex] x ∈ (-∞,-3) ∨ ([latex] frac{1}{2} [/latex], +∞) B) [latex]-3x^2 -2x +1 = 0[/latex] Δ = [latex]4 + 12 = 16[/latex] [latex]x_1 = frac{2-4}{-6} = frac{1}{3}[/latex] [latex]x_2 = frac{2+4}{-6} = -1[/latex] x ∈ (-∞, -1> ∨ <[latex]frac{1}{3}[/latex], +∞) c)  [latex](x+3)(x-1) = x(x-3) \ x^2 +2x - 3 = x^2 - 3x \ x = frac{3}{5}[/latex]