Daje naj ! Zadanie związane jest z drugą zasadą dynamiki newtona !

[latex]a)\\F_{w} = 5N-3N = 2 N\\a = frac{F_{w}}{m} = frac{2N}{2kg} = 1frac{N}{kg} = 1frac{m}{s^{2}}[/latex] [latex]b)\\F_{w} = 6N - (4N+1N) = 6N-5N = 1 N\\a = frac{F_{w}}{m} = frac{1N}{3kg}=0,(3)frac{m}{s^{2}}approx0,3frac{m}{s^{2}}[/latex] [latex]c)\\F_{w} = (1N + 6N)-2N = 7N - 2N = 5 N\\a = frac{F_{w}}{m} = frac{5N}{2kg} = 2,5frac{m}{s^{2}}[/latex]