[latex](x-a)^2+(y-b)^2=r^2[/latex] Wstawiamy punkty do wzoru [latex](6-a)^2+(-1-b)^2=r^2[/latex] [latex](2-a)^2+(-9-b)^2=r^2[/latex] [latex](2-a)^2+(-1-b)^2=r^2[/latex] Stąd mamy [latex](6-a)^2+(-1-b)^2=(2-a)^2+(-9-b)^2[/latex] [latex](6-a)^2+(-1-b)^2=(2-a)^2+(-1-b)^2[/latex] czyli [latex]36-12a+a^2+1+2b+b^2=4-4a+a^2+81+18b+b^2 [/latex] [latex]36-12a+a^2+1+2b+b^2=4-4a+a^2+1+2b+b^2[/latex] Zatem [latex] left { {{-8a-16b=48} atop {-8a=-32}} ight. = extgreater a= 4 [/latex] [latex]-32-16b=48= extgreater -16b=80= extgreater b=-5[/latex] Czyli środek S(4,-5) r^2=(6-4)^2+(-1-(-5))^2 r^2=2^2 + 4^2 r^2=4+16 r^2=20 r=2 pierwiastki z 5 Równanie ogólne: (x-4)^2+(y+5)^2=20 Równanie kanoniczne: x^2-8x+16+y^2+10y+25=20, czyli x^2-8x+y^2+10y+21=0
