Fizyka, jedno krótkie zadanie, DAM NAJ, pilne

[latex]dane:\T_1 = 10^{o}C\T_2 = 100^{o}C\Delta T = 90^o}C\t = 5 min = 5*60s = 300 s\R = 50 Omega\U = 230 V\C = 4200frac{J}{kg*^{o}C}\szukane:\m = ?[/latex] [latex] W= E_{el} = U*I*t\\ale I=frac{U}{R}\\W = U*frac{U}{R}*t\\W = frac{U^{2}*t}{R}\oraz\W = Q = m*C*Delta T\\m*C*Delta T= frac{U^{2}*t}R} /:C*Delta T\\m = frac{U^{2}*t}{R*C*Delta T}=frac{230{2}*300}{50*4200*90} kg\\m = 0,84 kg[/latex] [latex]Odp. C[/latex]