Zadanie z elektro techniki potrzebne na dzisiaj pomocy!

1. I=10 A; U=120 V R=U/I=120/10=12Ω 2. R1=4Ω; R2=6Ω; R3=20Ω Rz=(R1+R2)R3/(R1+R2+R3)= (4+6)*20/(4+6+20)=6,6667 Rz=6 i 2/3 Ω 3. Uab=100 V I1=Uab/(R1+R2)= 100/(4+6)=10 A I2=Uab/R3= 100/20=5 A I=I1+I2=15 A I=Uab/Rz= 100/(6+2/3)=15 A