Proszę o rozwiązanie przykładów umieszczonych w załączniku. Za wykonanie tych przykładów dam naj !

*[latex]frac{x+3}{2}-frac{x+1}{3}=frac{3}{2}/*6[/latex] [latex]3(x+3)-2(x+1)=3*3[/latex] [latex]3x+9-2x-2=9[/latex] [latex]x=9-7[/latex] [latex]x=2[/latex] *[latex]x+(1+x)sqrt{5}=1[/latex] [latex]x+sqrt{5}+sqrt{5}x=1[/latex] [latex]x+sqrt{5}x=1-sqrt{5}[/latex] [latex]x(1+sqrt{5})=1-sqrt{5}/:(1+sqrt{5})[/latex] [latex]x=frac{1-sqrt{5}}{1+sqrt{5}}=frac{1-2sqrt{5}+5}{1-5}=frac{6-2sqrt{5}}{-4}=frac{sqrt{5}-3}{2}[/latex] *[latex]5(x-1)^2-2(x+3)^2=3(x+2)^2-7(6x-1)[/latex] [latex]5(x^2-2x+1)-2(x^2+6x+9)=3(x^2+4x+4)-42x+7 [/latex] [latex]5x^2-10x+5-2x^2-12x-18=3x^2+12x+12-42x+7 [/latex] [latex]3x^2-22x-13=3x^2-30x+19 [/latex] [latex]8x=32/:8 [/latex] [latex]x=4[/latex] *[latex]xsqrt{2}-3=x-1[/latex] [latex]xsqrt{2}-x=-1+3 [/latex] [latex]x(sqrt{2}-1)=2/:(sqrt{2}-1)[/latex] [latex]x=frac{2}{(sqrt{2}-1)}=frac{2(sqrt{2}+1)}{2-1}=frac{2sqrt{2}+2}{1}=2sqrt{2}+2[/latex] *[latex](x-3)(x+4)-2(3x-2)=(x-4)^2[/latex] [latex]x^2+4x-3x-12-6x+4=x^2-8x+16 [/latex] [latex]-5x+8x=16+8 [/latex] [latex]3x=24/:3[/latex] [latex]x=8[/latex] *[latex]3(x+1)^2+(x-4)^3=101+(x-3)^3[/latex] [latex]3(x^2+2x+1)+x^3-3x^2*4+3x*16-64=[/latex][latex]101+x^3-3x^2*3+3x*9-27 [/latex] [latex]3x^2+6x+3+x^3-12x^2+48x-64=74+x^3-9x^2+27x [/latex] [latex]-9x^2+54x+9x^2-27x=74+61 [/latex] [latex]27x=135/:27[/latex] [latex]x=5[/latex]