bardzo proszę o pomoc będę wdzięczna daje naj ważne na dziś

symbol : ^2 będzie oznaczało : do potęgi 2 a) (x-2)^2+(2x-3)^2=(x-2)(x-2)+(2x-3)(2x-3)=x^2-2x-2x+4+4x^2-6x-6x+9=5x^2-16x+13 b)(3y-1)^2-(2y-5)(2y+5)-3y^2=(3y-1)(3y-1) - (2y-5)(2y+5)-3y^2=9y^2-3y-3y+1-4y^2_10y-10y-25-3y^2=2y^2-6y-24 c) (5a-2)(5a+2)-(3a-1)^2+4a^2=25a^2+10a-10a-4-(3a-1)(3a-1)+4a^2=25a^2+10a-10a-4-9a^2-3a-3a+1+4a^2=20a^2-6a-3 d) (4b+3)^2-2(b-3)(b+3)-(b-1)^2=(4b+3)(4b+3)-2b+6-2b-6-(b-1)(b-1)=16b^2+12b+12b+9-4b-b^2-b-b+1=15b^2_18b+10 e) 5(x+2)^2-3(x-3)^2-(x+5)(x-5)=5(x+2)(x+2)-3(x-3)(x-3)-(x+5)(x-5)=5x^2+2x+2x+4-3x+9-3x+9-x^2-5x+5x-25=4x^2-2x-12 f)6(y-2)(y+2)+(3y-2)^2-4(y-1)^2=6y^2+2y-2y-4+(3y-2)(3y-2)-4(y-1)(y-1)=6y^2+2y-2y-2y-4+9y^2-6y-6y+4-4y^2-y-y+1=11y^2-14y+1 g)2(4a^2_2ab_2ab+2ab+b^2)-(4b^2+2ab+2ab+a^2)+a^2-2ab-2ab+4b^2=8a^2+4ab+4ab+2b^2-4b^2-2ab-2ab-a^2+a^2-2ab-2ab+4b^2=8a^2+2b^2 h) (4x+y)^2+(2y-3x)^2-(5x-y)(5x+y)=(4x+y)(4x+y)+(2y-3x)(2y-3y)-(5x-y)(5x+y)=16x^2+4xy+4xy+y^2+4y^2-6y^2-6xy+9xy-25x^2+5xy-5xy-y^2=-9+11xy-2y^2