Ile wynosi: √7√7 ----> pierwiastek z siedmiu pierwiastków z siedmiu log 2√2 z 1/4

[latex]sqrt{7sqrt{7}} = 7^{frac{1}{2}}*7^{frac{1}{4}}= 7^{frac{2}{4}}*7^{frac{1}{4}} =7^{frac{2}{4}+frac{1}{4}}= 7^{frac{3}{4}}[/latex] [latex]log_{2sqrt{2}}frac{1}{4} = x\\(2sqrt{2})^{x} = frac{1}{4}\\(2*2^{frac{1}{2}})^{x}= 2^{-2}\\(2^{frac{3}{2}})^{x} = 2^{-2}\\2^{frac{3}{2}x} = 2^{-2}\\frac{3}{2}x = -2 |*2\\3x = -4 /:3[/latex] [latex]x = -frac{4}{3}[/latex]