oblicz energie kwantu swiatla czerwonego o edługosci fali 610 nm

[latex]E_{Kwantu} = h frac{c}{lambda} [/latex] [latex]h= 6,628 * 10^{-34} J*s[/latex] [latex]E_{Kwantu} = 6,628*10^{-34}*frac{3*10^8 frac{m}{s}}{6,1*10^{-9}m} [/latex] [latex]E=6,628*10^{-34} J*s * 4,9*10^{-1} * 10^{17}[/latex] [latex]E=32,4772J*10^{-18}=3,24772*10^{-17}J[/latex]