Witam , Prosze o rozwiązanie a b c Daje naj ! Zadanie w załaczniku bardzo prosze o pomoc :)

[latex]c) =frac{2^7-2^2}{(4*3)^2*frac13(1+frac13+frac1{3^2})-80*(frac15+frac1{2*5}+frac1{4*5})}=frac{2^2(2^5-1)}{4^2*3^2*frac13(frac99+frac39+frac19)-80*frac15(1+frac12+frac14)}=\\ =frac{4(32-1)}{4^2*3*frac{13}9-16(frac44+frac24+frac14)} = frac{4*31}{4^2*frac{13}3-4^2*frac74} =frac{4*31}{4(4*frac{13}3-7)} = frac{31}{frac{52}3-7} = frac{31}{frac{52-21}{7}} = \\=frac{31}{frac{31}3} = 31*frac3{31} = 3[/latex] [latex]a) = frac{frac1{8^3}*(frac{24}{10})^2+10*(frac3{10})^3}{10*15^2} = frac{frac1{8^3}*frac{8^2*3^2}{10^2}+10*frac{3^3}{10^3}}{10*15^2} = frac{frac18*frac{3^2}{10^2}+frac{3^3}{10^2}}{10*3^2*5^2} = frac{frac{3^2}{10^2}(frac18+3)}{10*3^2*5^2} = \\=frac{3^2*(frac18+frac{24}8)}{10^2*10*3^2*5^2} = frac{frac{25}{8}}{10^3*25} = frac{25}{8*1000*25} = frac{1}{8000}[/latex] [latex]b) = 5^3*(frac1{5^3}*8^2(8+1)+(7*(7^2)^{-3}):7^{-5}) =\\=8^2*9 + 5^3*7*7^{-6}:7^{ -5} = 8^2*9+5^3*7^{1-6-(-5)} = \\=8^2*9+5^3*7^0 = 64*9 + 125 = 576 + 125 = 701[/latex]