[latex] a)\\ sqrt{ 1frac{9}{16}} *(-2)^2+1,2*frac{5}{12}=sqrt{ frac{25}{16}} *4+frac{12}{10}*frac{5}{12}= frac{5}{4}*4+frac{1}{2}=5+frac{1}{2}=5frac{1}{2}[/latex] [latex]b)\\ 2 frac{1}{2}- frac{1}{2}* sqrt[3]{3frac{3}{8}} +2^{-1}=2 frac{1}{2}- frac{1}{2}* sqrt[3]{ frac{27}{8}} + frac{1}{2}=\\=2 frac{1}{2}- frac{1}{2}* frac{3}{2} + frac{1}{2}=2 frac{1}{2}- frac{3}{4} + frac{1}{2}= 2 frac{2}{4}- frac{3}{4} + frac{2}{4}=1frac{3}{4}+frac{2}{4}=1frac{5}{4}=2 frac{1}{4}[/latex] [latex]c)\\( frac{3}{4})^{-1}-(-1 frac{1}{3})^2:0,9 = frac{4}{3} -(- frac{4}{3})^2 :frac{9}{10} = frac{4}{3} -( frac{16}{9})*frac{10}{9} =\\=frac{4}{3} - frac{160}{81})=frac{108}{81} - frac{160}{81})=-frac{52}{81}[/latex] [latex]d))\\ 0,8* frac{3}{2^3} - frac{(-2)^3}{4} * 0,1 = frac{8}{10} * frac{3}{8} - frac{-8}{4} * frac{1}{10} = frac{3}{10} +frac{1}{5} =\\= frac{3}{10} +frac{2}{10} = frac{5}{10}=frac{1}{2}[/latex] [latex]e)\\(1 frac{1}{3})^2 * (- frac{1}{3})^{-2} - 1,9^0 * 3^{-1} = (frac{4}{3})^2 * (- frac{3}{1})^2 - 1* frac{1}{3} =\\= frac{16}{9} * frac{9}{1} - frac{1}{3} = 16 - frac{1}{3} = 15frac{2}{3}[/latex]
Oblicz:
a) √1i9/16×(-2)^2+1,2×5/12
b) 2i1/2-1/2×∛3i3/8+2^-1
c)(3/4)^-1-(-1i1/3)^2÷0,9
d)0,8×3/2^3 - (-2)^3/4×0,1
e)(1i1/3)^2×(-1/3)^-2-1,9^0×3^-1
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Zadanie z podręcznika Matematyka z plusem 3 str.52 zad.19
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