Nie mam pojęcia jak obliczać pierwiastki, na jutro muszę zrobić te zadania. Pilne, proszę o pomoc. :c

[latex]1. sqrt{ frac{16}{49} } = frac{ sqrt{16} }{ sqrt{49} } = frac{4}{7} \ sqrt{ frac{25}{81} } = frac{ sqrt{25} }{ sqrt{81} } = frac{5}{9} \ sqrt{ frac{121}{64} } = frac{ sqrt{121} }{ sqrt{64} } = frac{11}{8} =1frac{3}{8}\sqrt{ frac{400}{169} } = frac{ sqrt{400} }{ sqrt{169} } = frac{20}{13} =1frac{7}{13}[/latex] [latex]3. a)4 sqrt{2} + sqrt{8} =4 sqrt{2} + sqrt{4*2} =4 sqrt{2} +2 sqrt{2} =6 sqrt{2} \b) sqrt{32} -3 sqrt{2} = sqrt{16*2} -3 sqrt{2} =4 sqrt{2} -3 sqrt{2} = sqrt{2} \e) sqrt{18} + sqrt{72} + sqrt{98} = sqrt{9*2} + sqrt{36*2} + sqrt{49*2} =\3 sqrt{2}+6 sqrt{2} +7 sqrt{2} =16 sqrt{2} \[/latex] [latex]4.a)7 sqrt{5} + sqrt{20} =7 sqrt{5} + sqrt{4*5} =7 sqrt{5} +2 sqrt{5} =9 sqrt{5} \b) sqrt{48} - sqrt{3} = sqrt{16*3} - sqrt{3} =4 sqrt{3} - sqrt{3}= 3 sqrt{3} \d) sqrt{45} - sqrt{125} = sqrt{9*5} = sqrt{25*5} =3 sqrt{5} -5 sqrt{5} =-2 sqrt{5} [/latex] [latex]6.frac{1* sqrt{2} }{ sqrt{2} * sqrt{2}} =frac{ sqrt{2} }{2}\7. sqrt{12} * sqrt{3} = sqrt{12*3} = sqrt{36} =6\[/latex] [latex]8. sqrt[3]{ frac{8}{125} } = frac{ sqrt[3]{8} }{ sqrt[3]{125} } = frac{2}{5} \sqrt[3]{ frac{27}{8000} } = frac{ sqrt[3]{27} }{ sqrt[3]{8000} } = frac{3}{20} \ sqrt[3]{2frac{10}{27}} =sqrt[3]{ frac{64}{27} } = frac{ sqrt[3]{64} }{ sqrt[3]{27} } = frac{4}{3} =1frac{1}{3}\sqrt[3]{1frac{61}{64}} =sqrt[3]{ frac{125}{64} } = frac{ sqrt[3]{125} }{ sqrt[3]{64} } = frac{5}{4} =1frac{1}{4}[/latex]