Zad 29 zdjecie w załaczniku tylko zadanie 29 z góry dziękuje

zad 29 a) 1/x + 1/2x = 6 / * 2x     Df x ≠ 0 2 + 1 = 6 * 2x 3 = 12x x = 3/12 = 1/4 = 0,25 b) 2/3x + 5/6x = x / * 6x Df x ≠ 0 2 * 2+ 5 = 6x² 6x² = 4 + 5 = 9 x² = 9/6 x₁ = √(9/6) = 3/√6 = 3√6/6 = √6/3 x₂ = - √(9/6) = - 3/√6 = - 3√6/6 = - √6/3 c) 5 - (4x - 12)/x = x / * x   Df x ≠ 0 5x - 4x + 12 = x² x² - x - 12 = 0 Δ = (- 1)² - 4 * 1 * (- 12) = 1 + 48 = 49 √Δ = √49 = 7 x₁ = (1- 7)/2 = - 6/2 = - 3 x₂ = (1 + 7)/2 = 8/2 = 4 d)   x/(x + 2) = 2x/(x - 2)    Df x ≠ 2 i x ≠ - 2 x(x - 2) = 2x(x + 2) x² - 2x = 2x² + 4x 2x² + 4x + 2x - x² = 0 x² + 6x = 0 x(x + 6) = 0 x = 0 ∪ x = - 6 e)   3/(x - 7) + 2/(x - 8) = 0 / * (x - 7)(x - 8)   Df x ≠ 7 i x ≠ 8 3(x - 8) + 2(x - 7) = 0 3x - 24 + 2x -14 = 0 5x - 38 = 0 5x = 38 x = 38/5 = 7 1/5 f)   x  +21/x = 10 / * x     Df x ≠ 0 x² + 21 = 10x x² - 10x + 21 = 0 Δ = (- 10)² - 4 * 1 * 21 = 100 - 84 = 16 √Δ =√16 = 4 x₁ = (10 - 4)/2 = 6/2 = 3 x₂ = (10 + 4)/2 = 14/2 = 7