PILNE !!! Oblicz wartość wyrażenia. Zadanie w załączniku.

[latex]a)\\frac{2}{1-sqrt{2}}+frac{2}{1+sqrt{2}} = frac{2(1+sqrt{2})+2(1-sqrt{2})}{(1-sqrt{2})(1+sqrt{2})} = frac{2+2sqrt{2}+2-2sqrt{2}}{1-2}=frac{4}{-1} = -4[/latex] [latex]b)\\frac{3}{sqrt{10}+sqrt{7}}-frac{6}{sqrt{10}-sqrt{7}} = frac{3(sqrt{10}-sqrt{7})-6(sqrt{10}+sqrt{7})}{(sqrt{10}+sqrt{7)(sqrt{10}-sqrt{7})}}=frac{3sqrt{10}-3sqrt{7}-6sqrt{10}-6sqrt{7}}{10-7}=\\frac{-3sqrt{10}-9sqrt{7}}{3}= -sqrt{10}-3sqrt{7} = -(sqrt{10}+3sqrt{7})[/latex] [latex]c)\\frac{-12}{2sqrt{3}-3sqrt{2}}+frac{6}{2sqrt{3}+3sqrt{2}} = frac{-12(2sqrt{3}+3sqrt{2})+6(2sqrt{3}-3sqrt{2})}{(2sqrt{3}-3sqrt{2})(2sqrt{3}+3sqrt{2})} = \\=frac{-24sqrt{3}-36sqrt{2}+12sqrt{3}-18sqrt{2}}{12-18} = frac{-12sqrt{3}-54sqrt{2}}{-6} = 2sqrt{3}+9sqrt{2}[/latex]