Potrzebuje jak najszybciej :D pytania w załączniku daje naj i duża ilość pkt ;) Pomóżcie xd

4. Kąt jest ostry ⇒ I ćwiartka ⇒ sinα>0 i cosα>0 [latex]tg alpha = frac{5}{6} \ ctg alpha = frac{1}{tg alpha } = frac{1}{frac{5}{6}}= frac{6}{5} \ tg alpha = frac{sin alpha }{cos alpha } = frac{5}{6} \ 6sin alpha=5cos alpha \ sin alpha = frac{5}{6} cos alpha \ sin^2 alpha +cos^2 alpha =1 \ (frac{5}{6} cos)^2 alpha+cos^2 alpha =1 \ frac{25}{36} cos^2 alpha+cos^2 alpha =1 \ frac{61}{36} cos^2 alpha =1 \ cos^2 alpha= frac{36}{61} \ cos alpha = frac{6}{sqrt{61}}[/latex] [latex]sin alpha = frac{5}{6} cos alpha= frac{5}{6} *frac{6}{sqrt{61}}=frac{5}{sqrt{61}} \ frac{ctg^2 alpha }{sin alpha cos alpha } = frac{( frac{6}{5} )^2}{frac{5}{sqrt{61}}*frac{6}{sqrt{61}}} = frac{ frac{36}{25}}{ frac{30}{61}} = frac{36*61}{30*25}= frac{366}{125}=2,928[/latex] 5. [latex]D=(0; frac{pi}{2} ) \ L=frac{1}{cos^2alpha}-1=frac{sin^2 alpha +cos^2alpha}{cos^2alpha}-1= frac{sin^2 alpha}{cos^2 alpha} +frac{cos^2 alpha}{cos^2 alpha}-1=tg^2 alpha +1-1= \ =tg^2 alpha =P[/latex]