help oblicz pole trojkata rownobocznego o boku 12cm

[latex]a = 12 cm \ \ P= frac{a ^{2} sqrt{3} }{4} \ \ P= frac{(12cm) ^{2} sqrt{3} }{4} \ \ P= frac{144 sqrt{3} cm ^{2} }{4} \ \ oxed {P=36 sqrt{3} cm ^{2} }[/latex]