zad.6. B.III prawo Coulomba zad.7. I: P, F , P ; V = λ / T zad.8. V = 2 m/s Fo = 40 N t = 5 s W = ? W = Fo *s V = s /t s = V*t s = 2 m/s * 5 s = 10 m W = 40 N * 10 m = 400 J zad.9. R = U / I Rx = 3 V / 0,2 A = 15 Ω Ry = 3 V / 0,1 A = 30 Ω Ry > Rx odp: B I zad.10 m₁ = 0,2 kg t₁ = 20 C m₂ = 0,1 kg t₂ = 60 C t₃ = 30 C tk = ? Q₁ = Q₂ [latex]m_1 * c_w * Delta T_1 = m_2 * c_w * Delta T_2 / : c_w[/latex] [latex]m_1 * ( t_3 - t_1 ) = m_2 * ( t_k - t_2 ) /:m_2[/latex] [latex]t_k - t_2 = frac{m_1 * ( t_3 - t_1 ) }{m_2} [/latex] [latex]tk - 60 C = frac{0,2 kg * 10 C }{0,1 kg } t_k - 60 C = 20 C tk = 20 C + 60 C = 80 C[/latex]
