Cześć, Mam problem z kilkoma zadaniami z matmy na niestety egzamin poprawkowy. Moglibyście pomóc mi z tymi zadaniami? Z góry dziękuję za waszą pomoc :) zad 1 a) Pole sześcianu wynosi 96cm2. Oblicz objętość tego sześcianu. b) Oblicz obwód kwadratu, je

1. a) P = 96 cm² i P = 6a² V = ? 6a² = 96     /:6 a² = 16 a = √16 = 4 cm V = a³ = (4cm)³ = 4cm · 4cm · 4cm = 64 cm³ b) P = 8100 m² i P = a² L = ? a² = 8100 a = √8100 = 90 m L = 4a = 4·90m = 360 m c) P = 150 cm² i P = 6a² V = ? 6a² = 150     /:6 a² = 25 a = 5 cm V = a³ = (5cm)³ = 5cm · 5cm · 5cm = 125 cm³ d) 312 000 000 = 3,12·10⁸ e) 107 000 000 = 1,07·10⁸ [latex]2.\a) sqrt{44} = sqrt{4cdot11} = sqrt{4}cdotsqrt{11} = 2sqrt{11}\\b) sqrt{45} = sqrt{9cdot5} = sqrt{9}cdotsqrt{5} = 3sqrt{5}\\c) sqrt[3]{48}=sqrt[3]{8cdot6} = sqrt[3]{8}cdotsqrt[3]{6} = 2sqrt[3]{6}\\d) sqrt[3]{54} = sqrt[3]{27cdot2} = sqrt[3]{27}cdotsqrt[3]{2} = 3sqrt[3]{2}\\e) sqrt{20} = sqrt{4cdot5} = sqrt{4}cdotsqrt{5} = 2sqrt{5}\\f) sqrt[3]{40} = sqrt[3]{8cdot5}= sqrt[3]{8}cdotsqrt[3]{5} = 2sqrt[3]{5}[/latex] [latex]g) sqrt[3]{108} = sqrt[3]{27cdot4} = sqrt[3]{27}cdotsqrt[3]{4} = 3sqrt[3]{4}[/latex] [latex]3.\a) 8sqrt{6} = sqrt{8^{2}cdot6} = sqrt{64cdot6} = sqrt{384}\\b) 4sqrt{7} = sqrt{4^{2}cdot7} = sqrt{16cdot7} = sqrt{112}\\c) 4sqrt[3]{10} = sqrt[3]{4^{3}cdot10} = sqrt[3]{64cdot10} = sqrt[3]{640}\\d) 5sqrt[3]{11} = sqrt[3]{5^{3}cdot11} = sqrt[3]{125*11} = sqrt[3]{1375}\\e) 2sqrt{7} = sqrt{2^{2}cdot7} = sqrt{4cdot7} = sqrt{28}\\f) 3sqrt[3]{4} = sqrt[3]{3^{3}cdot4} = sqrt[3]{27cdot4} = sqrt[3]{108}[/latex] [latex]g) frac{1}{2}sqrt{5} = sqrt{(frac{1}{2})^{2}cdot5} = sqrt{frac{1}{4}cdot5} = sqrt{frac{5}{4}}=sqrt{1frac{1}{4}}[/latex] [latex]4.\a)\P = 4sqrt{3}\i\P = frac{a^{2}sqrt{3}}{4}\h = ?\L = ?\\frac{a^{2}sqrt{3}}{4} = 4sqrt{3} |cdotfrac{4}{sqrt{3}}\a^{2} = 16\a = sqrt{16} = 4\\h = frac{asqrt{3}}{2}=frac{4sqrt{3}}{2} = 2sqrt{3}\\L = 3a = 3cdot4 = 12[/latex] [latex]b)\P = 8sqrt{3}\i\P = frac{a^{2}sqrt{3}}{4}\h = ?\L = ?\\frac{a^{2}sqrt{3}}{4} = 8sqrt{3} |cdotfrac{4}{sqrt{3}}\\a^{2} = 32\a =sqrt{32} = sqrt{16cdot2} = 4sqrt{2}\\h = frac{asqrt{3}}{2} = frac{4sqrt{2}*sqrt{3}}{2} = 2sqrt{6}\\L = 3a = 3cdot4sqrt{2} =12sqrt{2}[/latex]