Jak policzyc :(2/3×0,125+4,5):11/12=w wyniku ma wyjsc 5 prosze o rozpisanie daje naj

[latex] frac{ frac{2}{3} * frac{1}{8} +4,5} { frac{11}{12} } =( frac{2}{24} +4,5 )* frac{12}{11}= ( frac{1}{12} + frac{54}{12}) * frac{12}{11} = frac{55}{12}* frac{12}{11}= frac{5}{1} =5[/latex]

[latex]( frac{2}{3} *0,125+4,5): frac{11}{12}=( frac{2}{3} * frac{125}{1000}+ frac{45}{10})* frac{12}{11} =\\=( frac{2}{3} * frac{1}{8}+ frac{9}{2})* frac{12}{11}=( frac{1}{12}+ frac{54}{12})* frac{12}{11}=frac{55}{12}* frac{12}{11}= 5[/latex]