Iloczyn i iloraz potęg o jednakowych podstawach. Zadanie w załączniku (zadanie 6). Wzór: 2ᵃ × 2ᵇ = 2×2× ... ×2 × 2× ... ×2 = 2ᵃ⁺ᵇ 2ᵃ / 2ᵇ = 2×2× ... ×2 / 2× ... ×2 = 2ᵃ⁻ᵇ

[latex]a) 2^6cdot(-2)^3 : (-2)^8 = -2^9 : 2^8 = -2\ b) dfrac{5^7cdot(-5)^{24}}{5^{13}cdot5^{18}}=dfrac{5^7cdot5^{24}}{5^{31}}=dfrac{5^{31}}{5^{31}}=1\ c) dfrac{(-7)^{10}}{7^8cdot(-7)}=dfrac{7^{10}}{-7^9}=-7\ d) igg(-dfrac{1}{4}igg)^5:0,25^2=igg(-dfrac{1}{4}igg)^5:igg(dfrac{1}{4}igg)^2=igg(-dfrac{1}{4}igg)^3=-dfrac{1}{64}\ e) (-0,1)^3cdot0,1^4:0,1^2=(-0,1)^7:0,1^2=-0,1^5=-0,00001[/latex] [latex]f) dfrac{(-0,2)^3cdot0,2^4cdot(-0,2)^4}{-(-0,2^4cdot0,2^6)}=dfrac{-0,2^7cdot0,2^4}{-(-0,2^{10})}=dfrac{-0,2^{11}}{0,2^{10}}=-0,2[/latex]