Jakimi liczbami należy zastąpić kwadraciki zadanie 5 str 20 6 str 20 Zadanie w załączniku .

[latex]a)\ 1km = 1000m |()^2\ 1km^2=1000000m^2=oxed{10^6 m^2}\ 100km^2=10^6*100=10^6*10^2=oxed{10^8 m^2}[/latex] [latex]b)\ 1m = 100cm |()^2\ 1m^2=10000cm^2=oxed{10^4 cm^2}\ 10^5m^2=10^5*10^4=oxed{10^9 cm^2}[/latex] [latex]c)\ 1cm = 10mm |()^2\ 1cm^2 = 100mm^2=oxed{10^2 mm^2}\ 10cm^2=10*10^2=oxed{10^3 mm^2}[/latex] [latex]d)\ 1km = 1000m |()^3\ 1km^3 = 1000000000 m^3=oxed{10^9 m^3}\ 10km^3=10*10^9=oxed{10^{10} m^3}[/latex] [latex]a)\ (5^2)^3=(5^3)^2\ 5^6 =5^6\ \ b)\ (8^4)^2 extless 8^{4^{2}}\ 8^{8} extless 8^{16}\ \ c)\ ((frac{1}{2})^4)^5 extgreater ((frac{1}{2})^3)^6\ (frac{1}{2})^{20} extgreater (frac{1}{2})^{18}\ \ d)\ 2^{20}=4^{10}\ 2^{20}=(2^2)^{10}\ 2^{20}=2^{20}\ \ e)\ 0,5^6 extless 0,25^4\ 0,5^6 extless (0,5^2)^4\ 0,5^6 extless 0,5^8\ \ f)\ (frac{1}{49})^8 extgreater (frac{1}{7})^{12}\ ((frac{1}{7})^2)^8 extgreater (frac{1}{7})^{12}\ (frac{1}{7})^{16} extgreater (frac{1}{7})^{12}\ \ g)\ 16^8 extgreater 64^5\ (4^2)^8 extgreater (4^3)^5\ 4^{16} extgreater 4^{15}\ \ [/latex] [latex]h)\ 0,027^5 extless 0,09^{9(?)}\ (0,3^3)^5 extless (0,3^2)^{9(?)}\ 0,3^{15} extless 0,3^{18}\ \ i)\ (frac{4}{9})^3=(frac{8}{27})^2\ (frac{2}{3})^6=(frac{2}{3})^6[/latex]