Zadanie 3.38 i 3.40. Pilne na zaraz!! Dam naj

[latex]3.38\dane:\s = 36 m\t = 2 s\szukane:\v = ?\\Rozwiazanie:\\v = frac{s}{t}\\v = frac{36m}{2s} = 18frac{m}{s}\\18frac{m}{s} = 18cdotfrac{0,001km}{frac{1}{3600}h} = 64,8frac{km}{h}[/latex] [latex]3.40\dane:\v = 2frac{m}{min}\t = 15 min\szukane:\s = ?\\Rozwiazanie:\\s = vcdot t\\s = 2frac{m}{min}cdot15min = 30 m[/latex]