M NaNO₃ = 85 g/molM Na₂SO₄ = 142 g/mol--------------------------------------------------------------------------m NaNO₃ = 1,7 gn NaNO₃ = 1,7 g / 85 g/mol = 0,02 molaNaNO₃ ----> Na⁺ + NO₃⁻ n Na⁺ = NaNO₃ = 0,02 mola--------------------------------------------------------------------m Na₂SO₄ = 7,1 gn Na₂SO₄ = 7,1 g / 142 g/mol = 0,05 molaNa₂SO₄ ----> 2Na⁺ + SO₄²⁻n Na⁺ = 2 * Na₂SO₄ = 2 * 0,05 mola = 0,1 mola-----------------------------------------------------------------------Suma ilości moli Na⁺∑ Na⁺ = 0,02 mol + 0,1 mol = 0,12 mol----------------------------------------------------------------------c mol Na⁺ = n Na⁺ / V = 0,12 mol / 3 dm³ = 0,04 mol/dm³
