Dla 5 alkanów : metan, etan, propan, butan, pentan oblicz zawartość procentową, wyznacz stosunek wagowy węgla do wodoru... Na jutro muszę mieć pomocy daje 60pkt ☺

Metan CH₄ m = 12u + 4*1u = 16u %C = 12u*100%/16u = 75% %H = 4u*100%/16u =25% mC/mH = 12/4 = 3/1 Etan C₂H₆ m = 2*12u + 6*1u = 30u %C = 24u*100%/30u = 80% %H = 6u*100%/30u =20% mC/mH = 24/6 = 4/1 Propan C₃H₈ m = 3*12u + 8*1u = 44u %C = 36u*100%/44u = 81,8% %H = 8u*100%/44u =18,2% mC/mH = 36/8  = 9/2 Butan C₄H₁₀ m = 4*12u + 10*1u = 58u %C = 48u*100%/58u = 82,76% %H = 10u*100%/58u =17,24% mC/mH = 48/10  =  24/5 Pentan C₅H₁₂ m = 5*12u + 12*1u = 72u %C = 60u*100%/72u = 83,3% %H = 12u*100%/72u =16,7% mC/mH = 60/12  =  5/1