Prosze pomozcie rozwiazac mi to zadanie z zalacznika. To na dzisiaj a nie potrafie tego oblivzyc naprawde blagam

Pierwszy dzień  ;  prędkość  2m/s    zamienić  na    ........ km/h 1 godz. = 3 600 s        to  2*3 600 = 7 200m  zamieniamy  na 7.2 km. ```````````````````````````````````````````````````````````````````````````````````````   2 m/s  =  7.2 km/h. `````````````````````````````````````````````````````````````````````````````````````  Drugi dzień    prędkość =  droga : czas          V = 20 km / 5 godz. =  4 km/h ```````````````````````````````````````````````````````````````````````````````````````````````````` Prędkość średnia  ;  dodać obie prędkości  i wynik podzielić na 2   V śr  =  ( 7.2 km/ h   +   4  km/ h )  : 2  =11.2 km/h  :2  = 5.6 km/h. ````````````````````````````````````````````````````````````````````````````````````````` odp.  średnia  prędkość  5.6 km/h    ;  C

[latex]dane:\s_1 = 36 km\v_1 = 2frac{m}{s} = 2cdotfrac{0,001km}{frac{1}{3600}h} = 7,2frac{km}{h}\s_2 = 20 km\t_2 = 5 h\szukane:\v_{sr} = ?\\v_{sr} = frac{s}{t} \\s = s_1 + s_2 = 36km + 20km = 56 km\t = t_1 + t_2= frac{s_1}{v_1}+5h = frac{36}{7,2}h + 5h = 5h + 5h = 10 h\\v_{sr} =frac{56km}{10h} = 5,6frac{km}{h}\\Odp. C) [/latex]