Bardzo prosze o pomoc. dam naj.. Zad nr 2 /powtorzenie/ zadanie w pliku

[latex]a) (3+sqrt{2})^{2}=9+12sqrt{2}+2=11+12sqrt{2}\b)(1-sqrt{5})^{2}=1-2sqrt{5}+5=6-2sqrt{5}\c)(4-3sqrt{2})^{2}=16-24sqrt{2}+18=34-24sqrt{2}\d)(2sqrt{7}+3)^{2}=28+12sqrt{7}+9=37+12sqrt{7}\e)(2sqrt{5}+sqrt{3})^{2}=20+4sqrt{15}+9=29+4sqrt{15}\f)(sqrt{6}-2sqrt{3})^{2}=6-4sqrt{18}+12=18-4sqrt{9*2}=18-sqrt{2}\g)(sqrt{8}-frac{sqrt{2}}{2})^{2}=8-frac{2*sqrt{16}}{2}+frac{2}{4}=8-frac{2*4}{2}+frac{2}{4}=8+frac{18}{4}=12frac{1}{2}[/latex] [latex]h)(frac{sqrt{2}}{2}+sqrt{3})^{2}=frac{2}{4}+frac{sqrt{6}}{2}+3= frac{2}{4} +frac{2sqrt{6}}{4} + frac{12}{4} = frac{14+2sqrt{6}}{4}=frac{7+sqrt{6}}{2}[/latex]