oblicz ciepło potrzebne do ogrzania i stopienia lodu o temp. potrzebnej -30*C I MASIE 2 KG

t₁ = - 30 C t₂ = 0 C ΔT = 0 C - (-30 C ) = 30 C m = 2 kg cl = 2100 J/kg * C ct = 335000 J/kg Q = Q₁ + Q₂ [latex]Q = m * cl * Delta T + m * c_t = m ( c_l * Delta T + c_t )[/latex] [latex]Q = 2 kg * ( 2100 frac{J}{kg * C } * 30 C + 335000 frac{J}{kg } ) = 2 kg * 398000 frac{J}{kg } = 796000 J[/latex] [latex]Q = 796 kJ[/latex]