Proszę o zrobienie ZADANIA 1. Treść zadania w załączniku jak i przykładowe rozwiązanie. Bardzo pilne !!!

o=6(cos4/3π+jsin4/3π); 4/3π=π+π/3; cos(π+π/3)=-cosπ/3; sin(π+π/3)=-sinπ/3 zo=6(-1/2-j√3/2)=-3-j3√3 z1=3(cos3/2π+jsin3/2π); ; 3/2π=π+π/2 z1=3(0-j)=0-j3 z2=6(cos5/2π+jsin5/2π; 5/2π=2π+π/2 z2=6(0+j)=0+6j z3=√2(cos7/4π+jsin7/4π); 7/4π=6/4π+π/4=3/2π+π/4 z3=√2(√2/2-j√2/2)=1-j z4=6(cos11/6π+jsin11/6π); 11/6π=2π-π/6 z4=6(√3/2-j/2)=3√3-j3 z5=3(cos0-jsin0)=3-j0 z6=6(cosπ/6+jsinπ/6)=6(√3/2+j/2)=3√3+3j z7=√2(cosπ/4+jsinπ/4)=√2(√2/2+j√2/2)=1+j z8=6(cosπ/3+jsinπ/3)=6(1/2+j√3/2)=3+j3√3 z9=3(cosπ/2+jsinπ/2)=3(0+j)=0+3j z10=6(cos2/3π+sin2/3π); 2/3π=π-π/3 z10=6(-1/2+j√3/2)=-3+j3√3 z11=√2(cos3/4π+jsin3/4π); 3/4π=π-π/4 z11=√2(-√2/2+j√2/2)=-1+j z12=6(cos5/6π+jsin5/6π); 5/6π=π-π/6 z12=6(-√3/2+j/2)=-3√3+j3 z13=3(cosπ+jsinπ)=3(-1+j0)=-3+j0 z14=6(cos7/6π+jsin7/6π); 7/6π=π+π/6 z14=6(-√3/2-j/2)=-3√3-j3 z15=√2(cos5/4π+jsin5/4π); 5/4π=π+π/4 z15=√2(-√2/2-j√2/2)=-1-j