W ciągu geometrycznym (an) dane są : a1=48 a2=16 . Oblicz iloraz tego ciągu oraz a5.

a2/a1 = 16/48 = 1/3 = q a5 = a2*q³ = 16*(1/3)³ = 16/27

[latex]a_1 = 48\a_2 = 16\n=5\q = ?\a_{5} = ?\\q = frac{a_2}{a_1} = frac{16}{48} = frac{1}{3}[/latex] [latex]a_{n} = a_1cdot q^{n-1}\\a_{5} = 48cdot(frac{1}{3})^{5-1} = 48cdot(frac{1}{3})^{4} = 48cdotfrac{1}{81} = frac{16}{27}[/latex]